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4 5 2 / !(f) f(t) = Rt −∞ δ(τ −2)dτ (g) g(t) = u(t)∗(δ(t2)−δ(t−2)) Solutions We use the followingproperties of the impulse function x(t)δ(t−t0) = x(t0)δ(t−t0) δ(at) = 1 a δ(t) Zb a δ(τ)dτ = (1 if a < 0 < b 0 otherwise d dt u(t) = δ(t) x(t) ∗δ(t−t0) = x(t−t0) (a) a(t) = δ(t) −2δ(t−2)t2δ(t) −2t2δ(t−2S u m m e r , t h e U n i t e d S t a t e s i s s t i l l e x p e r i e n c i n g t e n s o f t h o u s a n d s o f n e w c a s e s While the overall number of COVID19 diagnostic tests in our nation has expanded,
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