√100以上 Zî Ki xèê 334070
Pas opposed to k) takes the form 1 Ψ(x) = (2π~) 3/2 Z ∞ d3pΦ(p)eipx/~, −∞ 1 ∞ Φ(p) = (2π~)3/2 Z d3xΨ(x)e−ipx/~ −∞ (114) Just like we did in the 1DZ Ed ^ hZ/d/ ^ E &/E E >d X s } ^ íV P & Index Of Pub Wikimedia Images Wikipedia De 7 73 Z'î K'i xèê